Re: hi

Hi, please ignore the message sent above. (It is not from me! Do not click on the link.) 

Thank You and sorry for the trouble. 

On Sun, Jul 28, 2013 at 5:08 PM, kang yan <kangyan97@gmail.com> wrote:

 http://essence3.co.uk/cvw/drfbpsofjupae













 kang yan


















 7/28/2013 10:08:05 AM

hi

http://essence3.co.uk/cvw/drfbpsofjupae













kang yan


















7/28/2013 10:08:05 AM

FROM QUADRATIC FACTORISATION TO QUADRATIC FACTORISATION ...

REMEDIAL SESSION

Good morning everyone,

This is to confirm that we'll be having our remedial this THURSDAY (9th SEPTEMBER) at 0930 ... we'll meet in the LEARNING OASIS ... bring loads of writing paper and your calculator ... you would also need your LEARNING DEVICE in order to download the worksheet ...

Come prepared to work ... there is some issue with the notion of GRAPHS, its GRADIENT and the ALGEBRAIC PROBLEM SOLVING ...

JASON INGHAM

Summary for 30/08/10

Yeo Jun Peng (22)- 30/8/10
If a question asked you about drawing the Line Of Symmetry, it means cutting the graph into two exactly similar parts facing each other like a mirror image.
Example:

IMPORTANT*

(a+b)(a+b)=(a)(a)+(2ab)+(b)(b) AND (a-b)(a-b)=(a)(a)-(2ab)+(b)(b) are called: Perfect Squares

While

(a+b)(a-b)=(a)(a)-(b)(b) are called: Difference Of 2 Squares

NOTE*: (a+b)(a+b)≠(a)(a)+(b)(b)

Good luck for your test on Friday:)

summary for 22/8/10

• NEVER cross multiply when there is no equal sign in the equation.
• Always do the inner most bracket first.
• All x intercept are called Roots.
• The y intercept of the curve line/parabola is the product of the y intercepts of the original straight lines.
• The x intercept of the curve is the same as the original straight lines.

Summary for 24/8/10

Tuesday's math lesson summary by Celine

Finding the equation of a line.

First deduce the gradient through the formula Rise over Run. Then substitute the the co-ordinates of the first point to deduce the y-intercept.

To get a faster equation: Change the equation into the format (x/a + y/b = 1)

Ex. y = 1/2x - 3

1/2x + y = -3

x/-2 + y/1 = -3

x/6 + y/-3 = 1 //

However, if the the question asks for the equation in terms of y=mx+c, just do it like this:

x/6 + y/-3 = 1

-3x/6+y = -3

-1/2x + y = -3

y = 1/2x -3//

Question: When doing x/a + y/b = 1, why must it equal to 1?