FROM QUADRATIC FACTORISATION TO QUADRATIC FACTORISATION ...

REMEDIAL SESSION

Good morning everyone,

This is to confirm that we'll be having our remedial this THURSDAY (9th SEPTEMBER) at 0930 ... we'll meet in the LEARNING OASIS ... bring loads of writing paper and your calculator ... you would also need your LEARNING DEVICE in order to download the worksheet ...

Come prepared to work ... there is some issue with the notion of GRAPHS, its GRADIENT and the ALGEBRAIC PROBLEM SOLVING ...

JASON INGHAM

Summary for 30/08/10

Yeo Jun Peng (22)- 30/8/10
If a question asked you about drawing the Line Of Symmetry, it means cutting the graph into two exactly similar parts facing each other like a mirror image.
Example:

IMPORTANT*

(a+b)(a+b)=(a)(a)+(2ab)+(b)(b) AND (a-b)(a-b)=(a)(a)-(2ab)+(b)(b) are called: Perfect Squares

While

(a+b)(a-b)=(a)(a)-(b)(b) are called: Difference Of 2 Squares

NOTE*: (a+b)(a+b)≠(a)(a)+(b)(b)

Good luck for your test on Friday:)

summary for 22/8/10

• NEVER cross multiply when there is no equal sign in the equation.
• Always do the inner most bracket first.
• All x intercept are called Roots.
• The y intercept of the curve line/parabola is the product of the y intercepts of the original straight lines.
• The x intercept of the curve is the same as the original straight lines.

Summary for 24/8/10

Tuesday's math lesson summary by Celine

Finding the equation of a line.

First deduce the gradient through the formula Rise over Run. Then substitute the the co-ordinates of the first point to deduce the y-intercept.

To get a faster equation: Change the equation into the format (x/a + y/b = 1)

Ex. y = 1/2x - 3

1/2x + y = -3

x/-2 + y/1 = -3

x/6 + y/-3 = 1 //

However, if the the question asks for the equation in terms of y=mx+c, just do it like this:

x/6 + y/-3 = 1

-3x/6+y = -3

-1/2x + y = -3

y = 1/2x -3//

Question: When doing x/a + y/b = 1, why must it equal to 1?

Summary for 20/8/10's lesson...

Kristin Chai(1)- 20/8/10(Friday)

Linear Graphs
For questions similar to example 07 you must REMEMBER that the final line MUST be a equation nothing else.
Also, y=mx+c. In order to find C we need to know y.Therefore,there will only have 1 unknown.
We can substitute some of the coordinates and we can find out what is C.

Finding the Gradient:
We need to change the equation into y=mx+c.
When the questions say it is parallel that means the gradient is the same.
Also,if the line is horizontal the gradient will be 0.

SUMMARY OF LINEAR EQUATIONS ...

ANONYMOUS - 17th August 2010

1. Today we reconsidered the linear equation & the general form of a linear equation is y = mx + c
2. where by the m refers to the GRADIENT
3. where c is the Y-INTERCEPT (or the value of y when x = 0)
4. m is POSITIVE when as x increases, y also increases
5. m is NEGATIVE when as x increases, y will decrease
6. m is ZERO when as x changes, y is constant (HORIZONTAL LINE)
7. m is undefined when x is constant and y changes (VERTICAL LINE)
8. X-INTERCEPT would be equal to -c / m ... (or the value of x when y = 0)

NOTE - c (or the constant in all the equation) is always the y-intercept, even for equations such as y = ax^2 + bx + c ...

Why do you think this is so? (HINT - look at point (3) above)

Prove point (8) for yourself ...